Simplify 11+secθ+11secθ.


Answer:

2cot2θ

Step by Step Explanation:
  1. Let,
    S= 11+secθ+11secθ
  2. On adding two fractions,
    S=(1secθ)+(1+secθ)(1+secθ)(1secθ)S=21sec2θ
  3. Using identity: sec2θ1=tan2θ,
    S=2(tan2θ)S=2cot2θ

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